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The point was that as mph is quite arbitrary unit it is practically impossible to see the amount of energy. If the speed of light was given in m/s then the amount of energy would have been easy to see. ie E = mc². c = 300 × 10^6 m/s, c² = 9 × 10^16 (m/s)², so with that equation 1kg of mass actually contains approximately 9 × 10^16 joules of energy which is a lot.

What would the equivalent thought process be in imperial units? Lets say you have 1 lb of mass and want to figure out the amount of energy contained in it with the equation E = mc² and c² being 3.47 × 10^10 miles per second, just to know the scale of things (which was kinda the point in the article imho). How would you do that?

edit: Another point of view: velocity and kinetic energy. E = 0.5mv², that should be familiar to anyone familiar to physics. So with a velocity of 5.5 × 10^9 inches per year you don't need a lot of mass to have a lot of energy, because the multiplier is so huge, right?



The point was that the text is intended to be understandable by people who are not necessarily familiar with physics, who don't have the faintest idea what a joule is and who wouldn't even understand scientific notation.




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