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Nice and short Haskell solution to #3: http://gist.github.com/617675

Ruby solutions to #1 and #2: http://gist.github.com/617676 http://gist.github.com/617678



Nice, but don't compute the length of a list if you don't have to.

(not . null) instead of (\x -> length x > 1) is shorter, and works on infinite lists also.

Edit: well, in case you would test for x>0.




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